A bear hides itself either behind bush A with probability 
or behind bush B with probability 
. A hunter have 5 bullets each of which can be fired either at bush A or B. Hunter hits each target independtly with an accuracy of 1/4. How many bullets can be fired at bush A to hit the bear with max. probability.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(1, 2)
Sol. Let T denotes the event that the bear is hit when x bullets are fired at bush A.
Let E 1 , E 2 denots the event as P(E 1 ) = ; P(E 2 ) 
= 
.
so P(T/E1) = 1 – (3/4) x and P(T/E 2 ) = 1 – (3/4) 10–x
Now P(x) = 5 C x 
Now put x = 1,2,3,4,5 in p(x) and find out the maximum p(x). for x = 1, 2 we get maximum value of p(x)
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems